Microsoft Transition Your MCTS on SQL Server 2008 to MCSA: SQL Server 2012, Part 1 : 070-457 Exam

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Microsoft 070-457 Exam Syllabus Topics:

Microsoft Transition Your MCTS on SQL Server 2008 to MCSA: SQL Server 2012, Part 1 Sample Questions:

1. You use a contained database named ContosoDb within a domain. You need to create a user who can log on to the ContosoDb database. You also need to ensure that you can port the database to different database servers within the domain without additional user account configurations. Which type of user should you create?

A) User mapped to an asymmetric key
B) SQL user without login
C) login mapped to a virtual account
D) Domain user

2. You have a database that contains the tables shown in the exhibit. (Click the Exhibit button).

You need to create a query for a report. The query must meet the following requirements:
NOT use object delimiters.
Return the most recent orders first.
Use the first initial of the table as an alias.
Return the most recent order date for each customer.
Retrieve the last name of the person who placed the order.
Return the order date in a column named MostRecentOrderDate that appears as the last column in the report.
The solution must support the ANSI SQL-99 standard.
Which code segment should you use?
To answer, type the correct code in the answer area.

A) select C.Lastname, P.MostRecentOrderDate from customers AS C inner join ( select customID, MostRecentOrderDate=max(orderDate) from orders group by customID
)P
on C.customerID=P.CustomerID
order by P.MostRecentOrderDate desc
B) SELECT c.CustomerID --optional c.LastName, max(o.OrderDate) 'MostRecentOrderDate' FROM Customer c LEFT OUTER JOIN Orders o ON o.CustomerID = c.CustomerID GROUP BY c.CustomerID, c.LastName ORDER BY 3 DESC
C) SELECT LastName, O.OrderDate AS MostRecentOrderDate FROM Customers AS C INNER JOIN Orders AS O ON CustomerID = O.CustomerID ORDER BY O.OrderDate DESC

3. You have a Microsoft SQL Server 2012 database that contains tables named Customers and Orders. The tables are related by a column named CustomerID. You need to create a query that meets the following requirements:
Returns the CustomerName for all customers and the OrderDate for any orders that they have placed.
Results must include customers who have not placed any orders.
Which Transact-SQL query should you use?

A) SELECT CustomerName, CrderDate FROM Customers JOIN Orders ON Customers.CustomerID = Orders.CustomerID
B) SELECT CustomerName, OrderDate FROM Customers CROSS JOIN Orders ON Customers.CustomerID = Orders.CustomerID
C) SELECT CustomerName, OrderDate FROM Customers LEFT OUTER JOIN Orders ON Customers.CustomerID = Orders.CustomerID
D) SELECT CustomerName, OrderDate FROM Customers RIGHT OUTER JOIN Orders ON Customers.CustomerID = Orders.CustomerID

4. You develop a Microsoft SQL Server 2012 database. You create a view that performs the following tasks:
Joins 8 tables that contain up to 500,000 records each.
Performs aggregations on 5 fields.
The view is frequently used in several reports. You need to improve the performance of the reports.
What should you do?

A) Convert the view into an indexed view.
B) Convert the view into a table-valued function.
C) Convert the view into a Common Table Expression (CTE).
D) Convert the view into a stored procedure and retrieve the result from the stored procedure into a temporary table.

5. You administer a Microsoft SQL Server database that supports a banking transaction management application. You need to retrieve a list of account holders who live in cities that do not have a branch location. Which Transact-SQL query or queries should you use? (Each correct answer presents a complete solution. Choose all that apply.)

A) SELECT AccountHolderlD FROM AccountHolder WHERE CityID <> SOME (SELECT CityID FROM BranchMaster)
B) SELECT AccountHolderID FROM AccountHolder WHERE CityID <> ANY (SELECT CityID FROM BranchMaster)
C) SELECT AccountHolderID FROM AccountHolder WHERE CityID NOT IN (SELECT CityID FROM BranchMaster)
D) SELECT AccountHolderID FROM AccountHolder WHERE CityID <> ALL (SELECT CityID FROM BranchMaster)

Solutions: